RSMSSB CET 2024 Answer Key Released: Objection Window Open Till November 28
The Rajasthan Subordinate and Ministerial Services Selection Board (RSMSSB) published provisional answer key for the Common Eligibility Test (CET) on November 20. Registered candidates who given the exam can download the RSMSSB CET 2024 answer key through official website at rsmssb.rajasthan.gov.in and rssb.rajasthan.gov.in.
RSMSSB organized the Common Eligibility Test (Graduate Level) examination from September 25 to September 28, 2024, at various exam centers all over India.
The deadline for the candidates can raise objections against any discrepancy RSMSSB CET 2024 answer key is November 28. Candidates need to provide their registration number and date of birth to download their RSMSSB CET 2024 answer key.
RSMSSB CET 2024: Objection Portal
Students have the opportunity to challenge the RSMSSB CET answer key if they find any issue or discrepancy in their answer key.
- Candidates can submit objections to the official answer key from November 26 to November 28, 2024. Make sure to submit it within the given deadline.
- There is a fee of Rs 100 for each objection. This fee is non-refundable and must be paid for each question a candidate wants to challenge. If multiple objections are raised, Rs 100 must be paid for each one.
Here is the step on how to raise the issue for the RSMSSB CET answer key:
- Go to the official portal at rsmssb.rajasthan.gov.in
- Log in to the portal and click the “Raise Objection” link
- Identify the question that has a problem.
- Provide a valid reason or evidence for why you think the answer is wrong.
- Pay the fee for each objection.
RSMSSB will review all submitted objections. If an objection is valid, corrections will be made to the answer key. After reviewing all objections, RSMSSB will publish the revised answer key.
RSMSSB CET 2024 Qualifying Marks
All General and OBC candidates need to score at least 40% marks and SC/ST students need to score at least 35% marks.
Follow PlanEdu for more educational updates
