JEE Main Normalisation Process 2025: Step-by-Step Guide to Calculate Scores
Introduction
The National Testing Agency (NTA) conducts the JEE Main examination and is a gateway for admission into prestigious engineering colleges in India, such as NITs, IIITs, and GFTIs. As the exam is held in multiple sessions and shifts, there can be variations in difficulty levels across these sessions. To ensure fairness and equity, the NTA employs the normalization process. This article provides a detailed explanation of the normalization process and step-by-step guidance on how scores are calculated.
What is the JEE Main Normalisation Process?
The JEE Main normalization process is a statistical method used to ensure that candidates from different shifts are evaluated on a common scale. This ensures that no candidate is unfairly advantaged or disadvantaged due to variations in the difficulty levels of different shifts.
Why is Normalisation Necessary?
Multiple Shifts and Variability:
JEE Main is conducted over several days and shifts. Despite efforts to maintain uniformity, slight differences in the difficulty level of question papers are inevitable.
Fair Ranking System:
Normalization ensures that the scores are comparable and ranks are allocated fairly across sessions.
Equity in Opportunities:
All candidates are placed on a level playing field, irrespective of the session they appeared in.
Key Terms in the JEE Main Normalisation Process
Raw Scores
These are the actual marks obtained by candidates in the JEE Main exam, calculated based on the number of correct and incorrect answers.
Percentile Scores
The percentile score indicates the percentage of candidates who scored equal to or below a particular candidate in the session.
Normalized Scores
These are the final scores calculated after the normalization process, used for preparing merit lists and rank allocation.
Step-by-Step Guide to Calculate JEE Main Normalised Scores
Step 1: Identify Raw Scores
The first step is calculating the raw score, which is derived as follows:
- +4 marks for every correct answer
- -1 mark for every incorrect answer
- No negative marking for unanswered questions
Step 2: Calculate Percentile Scores for Each Subject
Percentile scores are calculated separately for Physics, Chemistry, and Mathematics as well as the total raw score. The formula used is:
- Percentile Score = (Number of candidates who scored ≤ your raw score ÷ Total number of candidates in the session) × 100
Step 3: Derive Overall Percentile Score
Once percentile scores for each subject are calculated, an overall percentile score is derived based on the total raw score.
Step 4: Combine Percentiles Across Sessions
After calculating percentiles for all shifts, the scores are compared across sessions. This ensures that candidates from all shifts are evaluated on a uniform scale.
Step 5: Use the Final Normalisation Formula
The final step involves combining subject-wise and total percentile scores into a composite normalized score using NTA’s statistical formula.
Role of Normalisation in Rank Allocation
Once the normalized scores are calculated, they are used for rank allocation. The ranks are determined based on the overall percentile score, with ties resolved using subject-wise percentiles in the following order:
- Mathematics percentile
- Physics percentile
- Chemistry percentile
- Candidate’s age (older candidates are given preference)
Examples of JEE Main Normalisation
Let’s consider an example to illustrate the process:
- Candidate A (Session 1): Raw Score = 180, Percentile = 97.5
- Candidate B (Session 2): Raw Score = 170, Percentile = 98.0
- Although Candidate B has a lower raw score, their percentile score is higher due to the difficulty level of Session 2 being higher. Candidate B will be ranked higher than Candidate A.
Impact of Normalisation on Results
- Fairness Across Sessions: Candidates from tougher sessions are compensated, ensuring a level playing field.
- Transparency: The percentile-based ranking system ensures clarity and avoids disputes over unfair evaluation.
- Accurate Ranking: Normalisation accounts for variability in paper difficulty, resulting in a more accurate ranking system.
Conclusion
The JEE Main normalisation process is a well-structured method to ensure fairness and uniformity in evaluating candidates appearing in multiple shifts. By converting raw scores to percentiles and using these for rank calculation, the NTA ensures that no candidate is disadvantaged due to variations in exam difficulty. Aspiring engineers must understand this process thoroughly to comprehend their results better.
FAQs
1. What is the main purpose of the JEE Main normalisation process?
The process ensures fairness by compensating for variations in the difficulty levels of question papers across different shifts.
2. How are percentile scores different from raw scores?
Raw scores are the actual marks obtained, while percentile scores indicate the relative performance of a candidate compared to others in the same session.
3. Can a candidate’s percentile be higher with a lower raw score?
Yes, if the candidate’s session had a tougher paper, their percentile score could be higher despite a lower raw score.
4. How are ties resolved in the JEE Main ranking system?
Ties are resolved based on subject-wise percentiles in Mathematics, Physics, and Chemistry, followed by the candidate’s age.
5. Is the normalisation process used for both JEE Main and JEE Advanced?
No, the normalisation process is specific to JEE Main, as it is conducted in multiple sessions. JEE Advanced is conducted in a single session.
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